Command test in shell with or 1

[loloman]

Hi, how can i write in shell that :
If VAR # "valeur" or VAR # "valeur1" or VAR # "valeur2"
then
....
fi

 

[PHV]

Assuming # stands for different:
if [ "$VAR" != "valeur" -o "$VAR" != "valeur1" -o "$VAR" != "valeur2" ]
then
echo "Test passed"
else
echo "Test failed"
fi

Hope This Help, PH.
Want to get great answers to your Tek-Tips questions? Have a look at FAQ219-2884

 

[Ygor]

PHV, I think you have a logic error. The result would be "Test Passed" for any value of $VAR.

 

[vgersh99]

pat.sh valuer
pat.sh valuer3
pat.sh valuer999
pat.sh valuerA

pat.sh:

#!/bin/ksh

a="$1"

if [[ "$a" = valuer*([0-9]) ]] ; then
   echo "[$a] - FOUND"
else
   echo "[$a] - NOT found"
fi;

vlad
+----------------------------+
| #include<disclaimer.h> |
+----------------------------+

 

[PHV]

Ygor,
If VAR # "valeur" or VAR # "valeur1" or VAR # "valeur2"

I just translated the request.