Command SED Help 4

[AIXtexas]

Does anyone know an easy way to remove the preceeding (/) and the trailing (/.../*) from the below file?

/usr2/.../*
/usr2a/.../*
/usr3/.../*
/usr3a/.../*
/usr3b/.../*
/usr4/.../*
/usr4a/.../*


I only need the usrXX part of this file. It seems there should be a way to do it with SED, but I just cant figure it out. I'm writing a script where I'll need to strip the usrXX part out of this file and compare it with the df output.

Thanks,

Shane

 

[PHV]

sed 's!^/!!;s!/.*!!' /path/to/input

Hope This Helps, PH.
Want to get great answers to your Tek-Tips questions? Have a look at FAQ219-2884 or FAQ181-2886

 

[vgersh99]

echo '/usr2/foo/bar' | sed 's#^/[^/][^/]*/\(.*\)#\1#'

vlad
+----------------------------+
| #include<disclaimer.h> |
+----------------------------+

 

[AIXtexas]

Thanks everyone, that did the trick!

Shane

 

[vgersh99]

actually....

echo '/usr2/foo/bar' | sed 's#^/[^/][^/]*/##'

vlad
+----------------------------+
| #include<disclaimer.h> |
+----------------------------+

 

[PHV]

Another way:
awk -F/ '{print$2}' /path/to/input

Hope This Helps, PH.
Want to get great answers to your Tek-Tips questions? Have a look at FAQ219-2884 or FAQ181-2886

 

[p5wizard]

cut -d / -f 2 /path/to/file

should also do it (provided there's no double slashes anywhere in the file)...


HTH,

p5wizard

 

[AIXtexas]

Thanks everyone!

Its amazing that there's so many ways to accomplish the same thing.

Shane

 

[bigoldbulldog]

while read item
do
expr "$item" : "/\([^/]*\)/.*"
done < /path/to/input

# Far from ideal, but a useful model for certain situations

Cheers,
ND

bigoldbulldog@hotmail.com