Close an application, only if it's open?

[cold25]

Hi. My vb6 program launches a program (Acrobat Reader, for example), and then does some stuff to the opened program. When the vb6 program ends, it automacially closes the program that it launched earlier. However, the problem is that if the user closes the program that is launched by the vb6 program, and then tries to end the vb6 program, the vb6 program crashes, because it is trying to close a program that is no longer open.

So in attempting to solve this, I am trying to put in a simple "If" statement that would make the vb6 program only try to close the program that it launched, if that program is still open. I read that the AppActivate command returns a boolean value. So, I was thinking that something like the following might work:

If AppActivate "Acrobat Reader" = True Then
Call fSendKeys("%{F4}")
End If

However, it keeps calling the compile error: "Expected: Then or GoTo". I've also tried changing it to:
If AppActivate ("Acrobat Reader") = True Then
but it says "Expected Function or variable". I just want a statement that says "If the program's open, close it. If it's not, don't." Any ideas as to what I might be doing wrong here? Thanks in advance.
cold25

 

[gmmastros]

This may be a little lame, but.... You could add error handling with a resume next. Then, when your program tries to close an application that is already closed, it'll error, but get caught by the error handler.

It's not elegant, but it should work.

Ex.


On error Goto MyErrorHandler

' Code to close the running application

Exit Sub

MyErrorHandler:
Resume Next

 

[bjd4jc]

You could also look at thread222-63270

or if your systems are XP you could look into using WMI.