Clean text

[darioit]

Hello,
I take a list of zip file using command "7za.exe l file.zip", so I want use gawk to clean output

Ho can I clean this result:
2016-04-09 13:16:45 ....A 105907 123412 abc_def_c_hil.pdf
2016-04-09 13:16:45 ....A 105907 aa_bb_cc_dd.pdf
2016-04-09 13:16:45 ....A 105907 directory\ee_ff_gg_hh.pdf

to have this:
abc_def_c_hil.pdf
aa_bb_cc_dd.pdf
ee_ff_gg_hh.pdf

thank you in advance

 

[mikrom]

I you have the result in a file, e.g.

$ cat darioit.txt
2016-04-09 13:16:45 ....A 105907 123412 abc_def_c_hil.pdf
2016-04-09 13:16:45 ....A 105907 aa_bb_cc_dd.pdf
2016-04-09 13:16:45 ....A 105907 directory\ee_ff_gg_hh.pdf

then you can clean the output like this

$ cat darioit.txt | awk '{str=$NF; sub(/.*\\/,"", str); print str}'
abc_def_c_hil.pdf
aa_bb_cc_dd.pdf
ee_ff_gg_hh.pdf

 

[johnherman]

since the output is always in column 5 as delimited by space, you can print $5

awk -F" " '{print $5}' /path/to/file

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[johnherman]

My bad!
Since the output is always in the last column, you can print $NF

awk -F" " '{print $NF}' /path/to/file

==================================
advanced cognitive capabilities and other marketing buzzwords explained with sarcastic simplicity

 

[mikrom]

the output is always in the last column, you can print $NF

and if necessary you have to remove the directory name too - see my previous post