checking for a missing node 1

[jrenae]

Hello,

I'm trying to check for a missing node and display something.

If the node exists I show the child nodes, but how do I display something if it doesn't exist at all? The following works fine for showing what is there. But if Positions is missing I want to print out something like 'all'.

      <xsl:if test="Positions/Position != ''">
        <span style="font-weight:bold">
          <xsl:for-each select="Positions/Position">
          <xsl:value-of select="."/>
            <xsl:if test="position() != last()">, </xsl:if>
          </xsl:for-each>
        </span>
      </xsl:if>

Thanks for any help.

 

[tsuji]

something along this line preserving the part you are satisfied.
[tt]
[blue]<xsl:choose>
<xsl:when test="count(Positions)=0">
<span style="font-weight:bold"><xsl:text>all</xsl:text></span>
</xsl:when>
<xsltherwise>[/blue]
<xsl:if test="Positions/Position != ''">
<span style="font-weight:bold">
<xsl:for-each select="Positions/Position">
<xsl:value-of select="."/>
<xsl:if test="position() != last()">, </xsl:if>
</xsl:for-each>
</span>
</xsl:if>
[blue]</xsltherwise>
</xsl:choose>[/blue][/tt]

 

[jrenae]

Thank you tsuji! This worked perfectly.