check if DB field has text and display if yes

[coolicus]

I am trying to check if my field has data, if it does then display the header and the text within the field.

<?php 
if(!($rs1['other']==0)) { 
echo "<b>Other </b><br /><br />" .
echo $rs1['other'];
}
?>

Can someone point out where I am going wrong? So what I tried to do was

1. check if field 'other' has data
2. if yes then display heading and data in field
3. if not then do nothing

Thanks

 

[jpadie]

<?php 
if(!empty($rs1['other'])){
echo "<b>Other </b><br /><br />" .
echo $rs1['other'];
}
?>

in your usage you should try

<?php 
if($rs1['other'][red]![/red]==0) { 
echo "<b>Other </b><br /><br />" .
echo $rs1['other'];
}
?>

 

[coolicus]

haha, I was just coming back to say don`t worry I have found the solution when you replied!

I used

if($rs1['other']<="")

is this ok, or would I be better using !==0?

 

[jpadie]

empty() or !==

look at comparison operators in the php manual.