changing array

[pqe]

Hi,

I have a problem that has been bugging me for days

i have 2 arrays
A=[GGGGG GG GGGG GG GGGGG G G G ]
B=[10101100010101010101010101010110]

both are same in length

i need to change Array B in such a way that when Array A has a blank, the same position in Array B changes into character 'P'
below are my codes,this is a subroutine and arrays are predefined


int ABC()
{
int i;

for (i=0;i<=32;i++)
{if A = " "
(B = "P"
}

}


Is there anything wrong with the logic or syntax? Pls help. thanks.

 

[zeitghost]

It should be

if A[i] == " "

 

[pqe]

oh yea...correct A == " ", thanks!
can any1 spot anything else? thanks.

 

[zeitghost]

Wrong! Do it again!

It should be

if ( A[i] == ' ' )

' ' is a single space character
" " is a space character followed by a null.
i.e. it's a string.

 

[TrojanWarBlade]

First issue is the "i<=32".
Do you really want to check 33 characters?
I guess you actually wanted 32. In that case use "i<32".
Next issue is the comparison. Never use "=" for comparison. ALWAYS use "==" for comparison.
Third issue, a character is wrapped in single quotes, not double quotes. Double quotes is for multi-character strings.
Fourthly, if a function is defined as returning an int it MUST have a return statement.
Therefore:

int ABC(char *A, char *B)
{
  int i;

  for (i=0;i<=32;i++)
  {
    if(A[i] == ' ') {
      B[i] = "P";
    }
  }
}

Trojan.

 

[DaveSinkula]

A last issue is that the P assignment should be like this:

B[i] = [blue]'[/blue]P[blue]'[/blue];

 

[TrojanWarBlade]

Sorry, yep. That was a cut and paste thing! :-(


Trojan.