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Change the action code

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maas

Programmer
Sep 3, 2009
148
0
0
BH
Hello All,

I am having a label which it has in its action a hyperlink.

The code which I am using:

on (release)
{
get URL("Main/active.pdf","_blank")
}
and it will display the file after clicking on the label.

Now, Instead I want the label to open the "Main" Folder directory. I tried to remove the file name, but i did not success.

on (release)
{
get URL("Main/","_blank")
}

So, how to do that.

Thanks in advance for your help
 
It is opening the IE and shows at the address bar:

I do not want that, I want the Folder Main to be open and show it's contents
 
No, I don't mean that.

I would like to open a directory which is in c:/Main.

So, how to do that?
 
I am keeping a folder called "Main" and it has all the files and .fla files.

While clicking on a button, I want to open "Main/Contents".

How to do that?
 
This will be published in a CD
 
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