change hexadecimal value to double

[hallian92]

Is there a way that I can convert the following hexadecimal value into double:

String s = "16#1234#";

As converting this to long I am doing this
if (s.startsWith("16#&quot && s.endsWith("#&quot)
{
extractedValue = s.substring( 3, s.length()-1 );
longValue = Long.parseLong( extractedValue, 16 );
}


Is there any way I can do the same and change the above to double. If I use
doubleValue = Double.parseDouble(s);

gives me an error so I want to parse the above value and change it to double any tips of work arround. Is there any way that I change the string to double with a specified radix as there are no such methods like parseLong or parseInt that also except readix.
Thanks

 

[Targol]

I should have wrote the same code exept for cuttin your string :

String s = "16#1234#";

// As converting this to long I am doing this
StringTokenizer st = new StringTokenizer(s, "#");
if (st.countTokens() == 2) {
   int radix= new Integer(st.nextToken()).intValue();
   String hexStr = st.nextToken();
   longValue = Long.parseLong( hexStr, radix );
}

hope that helps. Water is not bad as soon as it stays out human body ;-)

 

[ChrisCarroll]

Can't you just finish off with
dbleValue= (double)longValue;
?