CFileDialog::GetFolderPath

[mzufferey]

Hi all,

I have a little problem with GetFolderPath.

First, I create an object f as this:

CFileDialog f(true, "txt", NULL, OFN_EXPLORER, "Texte Files (*.txt)|*.txt|", this);

Then, I want to retrive to open folder path of a file, but if I do this:

m_list.AddString((const char*) (LPCSTR) f.GetFolderPath());

I have an assertion problem.

So, how can I do, to obtaining the open folder path of a file.

Many thanks,

Michael.

 

[Cagliostro]

In my opinion the file name contains its full path. I don;t know in MFC, but for WinAPI it is true. Ion Filipski

filipski@excite.com

 

[Jcan]

Try using GetPathName() instead of GetFolderPath()
Here is an example....

CString strFilter = "Bitmap Files (*.bmp)|*.bmp|Jpeg Files(*.jpg)|*.jpg||";

CFileDialog fDlg (TRUE,NULL,NULL,OFN_HIDEREADONLY|OFN_OVERWRITEPROMPT,strFilter);

if (fDlg.DoModal() == IDOK)
{
CString m_filepath = _T(""
m_filepath.Format("%s",fDlg.GetPathName());

}

//now you have the full path

m_list.AddString(m_filepath);

 

[Jcan]

let me know if this works

 

[Nosferatu]

why do you have to cast the result to (const char *)???
I think you should drop the conversion...
[red]Nosferatu[/red]
We are what we eat...
There's no such thing as free meal...
once stated: methane@personal.ro

 

[IonelBurtan]

(const char*) (LPCSTR) ????
Double conversion to the same thing ???
(Because LPCSTR is defined as const char* )
Anyway I don't think you need a conversion at all.

GetFileName is the member function of file dialog for what you need.
GetFolderPath does not seem to be a member of CFileDialog.

HTH, s-)

Blessed is he who in the name of justice and goodwill, sheperds the weak through the valley of darkness...

http://www20.brinkster.com/ionelb