CCNA - Some questions

[StouffR]

I has been done my first CCNA exam and I failed at 844/1000.
To get it : 849/1000

But I saw some questions, and I can resolve it ?!

Can you help me ?

Questions :
1) A network is in this configuration, what's the best routing protocol choice ?
Net1 ---------Router 1----- Router ISP -------(Internet)
|
Net2
() RIP on both
() a static routeon R1 and BGP on Router ISP
() BGP on both
() defaults routes on both
() BGP on R1 & static route on Routeur ISP

2) How to choice the best routing protocol ?
Unless classfull/classless and network size ?

3) Can you confirm to me how I can see the size of RAM/FLASH and NVRAM avaible ?
With sh version but which field ?

Thanks for answers

 

[Jsteve]

1) a static routeon R1 and BGP on Router ISP

you would use static routes on your router mainly because you would need a powerful router (Proc and memory) to handle all of the Internet routes. because you only have one network a static route would be the best option that would keep the route table down and use less proc & memory.

ISPs will always use BGP.

2) mainly th size of the network and convergence time. Also base on vendor. EIGRP is Cisco only.

3)
AccessServer#sh ver
Cisco Internetwork Operating System Software
IOS (tm) 2500 Software (C2500-I-L), Version 12.1(19), RELEASE SOFTWARE (fc1)
Copyright (c) 1986-2003 by cisco Systems, Inc.
Compiled Tue 04-Mar-03 19:48 by kellythw
Image text-base: 0x03041ECC, data-base: 0x00001000

ROM: System Bootstrap, Version 11.0(10c), SOFTWARE
BOOTLDR: 3000 Bootstrap Software (IGS-BOOT-R), Version 11.0(10c), RELEASE SOFTWARE (fc1)

AccessServer uptime is 5 days, 21 hours, 50 minutes
System returned to ROM by power-on
System image file is "flash:c2500-i-l.121-19.bin"

cisco 2511 (68030) processor (revision M) with ***14336K/2048K bytes of memory.***
Processor board ID 06974655, with hardware revision 00000000
Bridging software.
X.25 software, Version 3.0.0.
1 Ethernet/IEEE 802.3 interface(s)
2 Serial network interface(s)
16 terminal line(s)
32K bytes of non-volatile configuration memory.
***8192K bytes of processor board System flash (Read ONLY) ***

Configuration register is 0x2102

 

[StouffR]

Thanks for your answer

For the size memory :
*** 14336K/2048K bytes of memory ****
14336K = free/avaible
2048K = occuped

size of memory = 14336K + 2048K = 16384K

that's correct ?

 

[ReadRight]

There are two types of DRAM memory in Cisco routers: primary and shared (packet). Primary memory is used to store the operating configuration, routing tables, caches, and queues. Shared memory is used to store incoming and outgoing packets.

So in your case you have:

14336K = primary
2048K = shared

size of memory = 14336K + 2048K = 16384K is correct

 

[StouffR]

So, it's DRAM type !

Ok ! Thanks !