cast int into char * 1

[netcomander]

Hi all,

I wonder how I cast int into char *.
e.g. I have an integer value (maby 356) and
want to make a char like "after 356 days".
But I have no idea, how to put this 356 into
this char array.

I would be glad for any hint

greetings markus

 

[Zyrenthian]

Here is how:

#include <stdlib.h>

sprintf(your_array,&quot;%d&quot;,356);

matt

 

[Zyrenthian]

Here is how:

#include <stdlib.h>

sprintf(your_array,&quot;after %d days&quot;,356);

matt

 

[Zyrenthian]

sorry about the double post. If you look up sprintf you will see that you can use

%d for digits
%f floating points
%s strings

just to name a few things you can do. You can also print in hex, a specified precision and more

Matt

 

[ekanth]

Hey,
Use itoa function provided if you work in DOS or Win. Or try writing a function which'll extract each digit from the number say(%) mod function. And then add 48 to them to get the actual ascii value. Add the result to the array. You can't cast it directly.
Regards,
Ekanth