Cannot Execute when trying to change IDLEOUT time

[jimv2502893]

Does anyone know why I cannot execute changes to the script I created to log users out automatically after 2 hours?

 

[keenanbr]

I presume you have IDLETIME=120 in /etc/default/idleout

to change type in command

idleout new_idleout_time

 

[jimv2502893]

I typed this command, how can I check to see if it worked?

 

[Annihilannic]

Log in and wait 120 minutes, see what happens. ;-)

ps -fp `cat /var/spool/lock/LCK..idleout` will tell you whether it's running.

You could make your own copy of /usr/bin/idleout and modify it, putting the following at line 181:

[tt]GREPFILE=/tmp/grep$$
awk -F: '$1 == "groupname" {print $4}' /etc/group | tr ',' '^J' > $GREPFILE[/tt]

"^J" is actually one control character; enter it in vi by typing Ctrl-V Ctrl-J while in insert mode. Change the previous line 181 to read:

[tt]LANG=C who -u | grep -f $GREPFILE > $TMPFILE[/tt]

And change the previous line 193 to read:

[tt]rm $TMPFILE $GREPFILE[/tt]

It's not foolproof, but it's a start. The first part creates a file containing the names of all members of "groupname", which of course should be changed to the group you want to use.

The second part filters only users that are in that group out of the who -u output. Annihilannic.

 

[Annihilannic]

In retrospect, I forgot to account for users' primary groups in /etc/passwd... Annihilannic.

 

[Annihilannic]

After the awk command mentioned above add this one to take account of the users' primary groups:

[tt]awk -F: '$4 == 123 { print $1}' /etc/passwd >> $GREPFILE[/tt]

Where 123 is the GID of the group in question. I've not tested any of this! Annihilannic.