Can code support two versions of PHP?

[suheil]

Hi

Is it possible to have PHP code support two versions of PHP? In particular, in PHP 4 I have code of the form

$obj->__clone();

Now, in PHP 5 that needs to change to:

clone $obj;

Is it possible to write code for this which will run on both PHP 4 and PHP 5? As a C programmer, I am thinking of something like:

  #if PHP_VERSION<5
      $obj->__clone();
  #else
      clone $obj;
  #endif

Thanks.

 

[Itshim]

You can use: phpversion()

The function returns a string containing the version of the currently running PHP parser. Which you can then manipulate to use in conditional statements.

 

[suheil]

Thanks. I tried that, but it seems its doesn't quite do what I'm looking for.
Something like:

       $phpversion = strval(substr(phpversion(),0,1));
       if ($phpversion<=4)
           echo "Version 4 or lower";
       else
           echo "Version 5 or higher";

works as expected.

But the following gives a parse error (under PHP4, the parse error is thrown by the PHP5 code, and vice-versa):

       $phpversion = strval(substr(phpversion(),0,1));
       if ($phpversion<=4)
           $dupl = $curr->__clone();
       else
           $dupl = clone $curr;

It seems the PHP parser wants to be able to parse all code in the file before it will display anything. (With "#if" in C-programming, the compiler only processes the relevant code as determined by the conditional.

 

[jpadie]

could you try moving the relevant calls out to an included file and then picking the relevant file out in your version picker script:

$phpversion = strval(substr(phpversion(),0,1));
       if ($phpversion<=4):
           require "php4include.php";
       else:
           require "php5include.php";
       endif;