call different files in a loop.

[scottpeter]

All,
I am new to Unix.I am trying to process 15 files in a shell script. The 15 files have the same name with the last characters as numbers 1 to 15.
I know that if it were a single digit number,I could have used [0-9]. But how will I call file ending with numbers above 9(from 10 to 15).
I cannot use *, because it will fetch some files that I do not need.
Also I cannot use a loop here. I need to call the files using a wild Card Character.

Thank You,
Scott

 

[Salem]

You could list the files in two steps, like so

myprog file[1-9] file1[1-5]

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[scottpeter]

Thanks a lot Salem,
Just a doubt, if there were files upto 40, which would be more efficient. using above or by using
myprog file? file??

Thanks,
Scott

 

[Salem]

There's probably not a lot in it - wildcards are expanded by the shell prior to running myprog

As you've mentioned, simply saying

myprog *

drags along files you don't want.

You could say for example

myprog file[1-9] file[1-4][0-9]

which would get file1 to file49

The only real difficulty is how many sub-patterns it takes to specify all the files you want to process. I normally try and arrange by either directory contents and/or file names that

myprog file*

gets all the files I am interested in, in one easy step.

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