C-problem (and it makes me mad)

[fheyn]

Hi,
there are days...
OK, my problem is like this :
I'm passing an array of char (cArray[50][20]) to a function which is declared like this : MyFunc(char *pArray). with pArray I'd like to access the array-items, which it does if I increment it by 20, but then it only gives me the first character of each array-item. To correct this, I use
strcpy(..) and all goes fine, but to me it looks like a really bad solution.

Someone has an idea to improve this ?
thanks

 

[hankgao0703]

I am not sure the following answer is the right one:

What you want to pass to the function is a 2-dimension array(Actually a pointer which points to the beginning address of the array), and the function declaration shows that you pass a char pointer. It's okay, on problem. The key is how to access the items in your function, you can do like the following:

MyFunc(char* pArray)
{
typedef char [50][20] myArrayType;
myArrayType * pWork = (myArrayType*)pArray;
//Now you can use pWork
pWork->[0][1] = 20; //Something like this.
...
}

Hope this can help.

 

[hankgao0703]

Sorry the correct code is the following:

void MyFunc(char* pArray)
{
typedef char myArrayType[50[20];
myArrayType * pWork = (myArrayType *)pArray;
//Now you cna use pWork
(*pWork)[0][0] = 20; //Something like this.
....
}

Sorry for the mistake.