Byte operation

[drkestrel]

I have an integer, for which I would like to interpret as an overflow value of the first 2 bytes

I tried

int myInt= 99999999999999999999999999999999999;
int first2Byte = myInt & 0xFFFF;
System.out.println (first2Byte);

However, the value seems too small to be true!!

What is the correct way of doing this?

 

[LittleWing]

how did u even get this to compile??? 99999999999999999999999999999999999 is WAY too big for an int

 

[Vepo]

Hi,

Yes that overflows maxint.
What do you mean with too small value? Let's take an example:


int myInt= 210000000;
int first2Byte = myInt & 0xFFFF;
System.out.println (first2Byte);

Gives you result 22656
which is 101100010000000 as binary

So the calculation goes like this:

1100100001000101100010000000 <- 210000000 as bin
0000000000001111111111111111 & <- FFFF (65535) bin
-----------------------------
0000000000000101100010000000

= 22656

I hope this made the situation clearer