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Button behaviour-opening a user entered url

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HubCapped

Programmer
Feb 8, 2005
4
GB
Basically, i have an html page, i have created a html form containing a text box which takes a url and a button which passes this url to an applet (on the same page) and then displays this url on the applet.
Currently this is all my applet does-display the URL from the form ,however i have added a button to the applet and i want to be able to click on this button and open the URL in the same window.
Does anyone know how to do this? Is it done in the java section?

This is my code do far:

HTML:
<form name="f1">
<b>Enter a website:p>
<input type="text" size="50" name="inurl">
<input type="button" value="Request URL" id="suburl" onClick="return validurl();">
</form>

<applet codebase="." code="javacode.class"
<param name="inurl" value="">
</applet>



JAVA:
public class javacode extends Applet
{
private Button clickButton;
String URL;

public void init()
{
URL = getParameter("inurl");

clickButton = new Button("Show URL");

}


public void updateURL(String newURL)
{
URL = newURL;
repaint();
}

public void paint(Graphics g)
{
g.drawString(URL,50 ,50);
}
 
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