boolean

[krava]

Hi,


I would like to evaluate $bool bash-variable with help of this awk command

eval $bool=\\$(awk -v str=$bn 'BEGIN{print (match(str,/tau(1|2|3|4|5|6)/) ? 1 : 0)}');

So, when str in awk match this regexp $bool should be 1 (otherwise 0)

Where I make misstake here?

thanks

 

[PHV]

Doesn't this suffice ?
bool=$(awk -v str=$bn 'BEGIN{print (match(str,/tau[1-6]/) ? 1 : 0)}')

Hope This Helps, PH.
FAQ219-2884
FAQ181-2886

 

[krava]

files that contain for example tau10, tau11 should not give back 1. How to do that?

 

[krava]

thanks. so your proposition:

bool=$(awk -v str=$bn 'BEGIN{print (match(str,/tau[1-6]/) ? 1 : 0)}')

works but, for files that contain tau10 or tau11, I would like to get 0 as an output. I tried something like this also but does not work

bool=$(awk -v str=$bn 'BEGIN{print (match(str,/tau(1\|2\|3\|4\|5\|6)/) ? 1 : 0)}');