Blank line inserted in output file from "ls -l" command 3

[pdtak]

I'm trying to capture the date/time portion of "ls -l" command as a file, but it puts a "blank line". How do I make it so that output file doesn't include a blank line?

Example 1 (saved as a variable works good):
var1=`ls -l /file1 | awk '{print $6,$7,$8}'`
echo $var1
May 24 23:06

Example 2 (blank line inserted):
ls -l /file1 | awk '{print $6,$7,$8}' > /tmp/out1
cat /tmp/out1
<blank line>
May 24 23:06

Any suggestion is appreciated.

 

[SamBones]

Try this...

ls -l | [b]tail +2[/b] | awk '{print $6,$7,$8}' > /tmp/out1
cat /tmp/out1

 

[pdtak]

That did the trick, adding "tail +2" to this command seems to have gotten rid of the leading blank line.
Thanks a bunch!

 

[SamBones]

But do you see why? Try these two commands and see the difference in output.

ls -l
ls -l | tail +2

The "[tt]tail +2[/tt]" is just removing the first line of output from the "[tt]ls -l[/tt]".

This would work too...

ls -l | [b]sed '1d'[/b] | awk '{print $6,$7,$8}' > /tmp/out1
cat /tmp/out1

That uses "[tt]sed[/tt]" to delete the first line of "[tt]ls -l[/tt]" output.

Hope this helps.

 

[PHV]

Why not simply this ?
ls -l | awk 'NF>8{print $6,$7,$8}' > /tmp/out1

Hope This Helps, PH.
FAQ219-2884
FAQ181-2886

 

[feherke]

Hi

Why the UUOT and UUOS while AWK can do that too ?

ls -l /file1 | awk '[highlight]NR>1[/highlight]{print $6,$7,$8}' > /tmp/out1

Example 1 (saved as a variable works good):
var1=`ls -l /file1 | awk '{print $6,$7,$8}'`

That only apparently works, actually the whitespaces get compromised due to word splitting, because you not quoted the string.


Feherke.

http://free.rootshell.be/~feherke/

 

[pdtak]

Thank you all for your inputs.
I gave you all a "STAR" for your awsomeness.