Binary Reverse

[xeneize]

May anyone help me to resolve this problem. How do I reverse a binary number. Lets say I have 00000001 00000010 10000000 01000000 then I have to show 10000000 01000000 00000001 00000010.
Thanks

 

[mingis]

int reverse(int value)
{
int ii;
int tmp=value;
int result=0;

for(ii=0; ii<sizeof(int)*8-1; ii++)
{
result|=tmp&1;
tmp>>=1;
result<<=1;
}

return(result);
}

 

[Zyrenthian]

How bout something like

struct flipIt{
unsigned bit0: 1;
unsigned bit1: 1;
unsigned bit2: 1;
unsigned bit3: 1;
unsigned bit4: 1;
unsigned bit5: 1;
unsigned bit6: 1;
unsigned bit7: 1;

void Reverse()
{
if(bit0!=bit7)
bit0^=bit7^=bit0^=bit7;

if(bit1!=bit6)
bit1^=bit6^=bit1^=bit6;

if(bit2!=bit5)
bit2^=bit5^=bit2^=bit5;

if(bit3!=bit4)
bit3^=bit4^=bit3^=bit4;
}
};

union flipUnion{
unsigned char c;
flipIt f;
};


flipUnion f;
f.c = value;
f.f.Reverse();


Just do it 8 bits at a time.

Matt

 

[Zyrenthian]

I wrote this up quick... im not sure if reverse works as intended. you get the idea though.. (I HOPE)

Matt