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Binary division
- Thread starter Drone38
- Start date
zBuilder
MIS
Right shifting will divide a binary # by 2.<br>You can also do division with multiple subtractions:<br>13 / 3 can be done by:<br><br>13 - 3 = 10<br>10 - 3 = 7<br>7 - 3 = 4<br>4 - 3 = 1<br><br>Since you had to subtract 4 times before you got a number less than the 3, the answer is 4 with 1 remainder. Basic math. <p> <br><a href=mailto:Kim_Christensen@telus.net>Kim_Christensen@telus.net</a><br><a href= Page</a><br>
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