Big problem: call a servlet from a form

[nino2000]

Jun 29, 2001 [2]
hi, I use NT, and I installed oracle8.1.6 with Jdeveloper3.1.6. I create a HTML page with a form
<FORM ACTION='test_servlet' METHOD=POST>
<INPUT TYPE=TEXT NAME='nom'> <INPUT TYPE='SUBMIT' VALUE='OK'> </FORM>
i created and compile a servlet, it doesn't work. I see the url with Iexplorer5:

http://localhost/web-inf/test_servlet

but the test_servlet.class is in the directory!
I use also servletrunner in ORACLE_HOME/apache/jsdk/bin
(ps: the example suplied with oracle (oracle_home/apache/jsdk/examples/jdcsurvey) don't work!)
servletrunner -p 8080 -d d:/oracle/ora81/apache/apache/htdocs/web-inf
(the servlet.properties is in the same directory)

I put jsdk.jar in the PATH and classPATH.
I create servlet.properties to define a name corresponding to the servlet.
the problem persists
Could you help me?

 

[nino2000]

Hi, I forgot to tell that my system use Apache with Jserv
Could someone put me on the way?

 

[sem]

Try to specify full path in action. As you may reffer to your sevlet as web-inf/test_servlet you should call it by the same full name.

 

[Guest_imported]

While running servlets . In the url we have to give port number( i.e. 8080).

In general we will register our servlets in servlets directory of web server. In the url there is no need to specify the directory name(i.e.

http://localhost:8080/sampleservlet).

Here sampleservlet is servlet name.

If you created a sub directory in the servelt (servlets)directory of web server then we have to give directory name after port no i.e.

http://localhost:8080/sample/sampleservlet.

Here sample is directory and sample servlet is servlet name.