bash script store array1 contents into new array problem 1

[rigstars2]

for ((i = 1; i <= 9; i=)); do
VAR=`sudo launchctl list | grep ${List[i-1]}` >/dev/null 2>&1
if [ "$VAR = "" ]; then
${List2[i-1]} = List[i-1] <---- the error says =: command not found ..what is wrong with my syntax
echo "${List2[i-1]}"
fi
done

 

[rigstars2]

btw, I have a type in the for loop. the i= should be i++
the problem still persists though ...

 

[LKBrwnDBA]

Try this:

. . .
  List2[i-1] = ${List[i-1]}

----------------------------------------------------------------------------
The person who says it can't be done should not interrupt the person doing it. -- Chinese proverb

 

[rigstars2]

nice try LKBrwnDBA but still says command not found ..I've been searching google ..maybe you can't assign contents of array
to another array ..?

 

[feherke]

Hi

There is a syntax error : you can not have spaces around the equal sign ( = ) :

[gray]# wrong[/gray]
List2[i-1][highlight #f66] [/highlight]=[highlight #f66] [/highlight]${List[i-1]}

[gray]# correct[/gray]
List2[i-1]=${List[i-1]}

Feherke.
feherke.ga

 

[LKBrwnDBA]

Ooops....


----------------------------------------------------------------------------
The person who says it can't be done should not interrupt the person doing it. -- Chinese proverb

 

[rigstars2]

feherke,

thanks, I'll try that when I go back to the office. Thanks!

 

[rigstars2]

Thanks feherke!! Works now