banner rotation

[skinster]

I have 3 banners being displayed but I dont want to display the same one twice how would i go abot that.
here is my code

Thanx aj

banpic = new Array();
banurl = new Array();

banpic[1]="

http://../angel.jpg";

banpic[2]="

http://../tower1.gif";

banpic[3]="

http://../danielle.jpg";

banpic[4]="

http://../tower2.gif";

banpic[5]="

http://../katja.jpg";

banpic[6]="

http://../tower3.gif";

banurl[1]="

http://www.site.com";

banurl[2]="

http://www.site.com";

banurl[3]="

http://www.site.com";

banurl[4]="

http://www.site.com";

banurl[5]="

http://www.site.com";

banurl[6]="

http://www.site.com";

function getban(){
var language = document.all ? navigator.userLanguage : navigator.language;
lang=0;
if( language && language.indexOf( "nl" ) != -1 ){
lang=3;
}

if(lang == 0){
banpicnum=rand(banpic.length-1);

return(&quot;<a href=javascript:banlink('&quot;+banurl[banpicnum]+&quot;')><img border=0 vspace=0 hspace=0 src=&quot;+banpic[banpicnum]+&quot;></a>&quot;
}
if(lang == 3){
banpicnum=rand(banpic_nl.length-1);
return(&quot;<a href=javascript:banlink('&quot;+banurl_nl[banpicnum]+&quot;')><img border=0 vspace=0 hspace=0 src=&quot;+banpic_nl[banpicnum]+&quot;></a>&quot;
}

calling banner function

<script>document.write(getban())</script>

 

[EdwardMartinIII]

Must it be a random selection? What's wrong with cycling through them in order? You could still pick a random banner with which to start, but then subsequently sequence through. Besides, your advertisers would probably appreciate knowing that they'll see more-or-less guaranteed 1/x coverage for x banners.

Cheers,

Edward &quot;Cut a hole in the door. Hang a flap. Criminy, why didn't I think of this earlier?!&quot; -- inventor of the cat door

 

[skinster]

Yes that would be good but How would I go about that Sorry for asking,I'm Pretty new at javascript

Thanx aj