awk syntax error

[yesornot]

hi
expected is to print single 'obsolete' or single 'input error' text (when conditions are met), but for the first if condition print (in this example):
1 3 fields, a>10
2 3 fields, a>10

what is wrong with "exit" in code below?

# echo "a b c\na b c"|awk -va=11 '{if (NF==3&&a>10) print NR,NF" fields, a>10"; else if (NF==2&&a<=10) print "obsolete"; else print "input error"}'
1 3 fields, a>10
2 3 fields, a>10
# echo "a b c\na b c"|awk -va=10 '{if (NF==3&&a>10) print NR,NF" fields, a>10"; else if (NF==2&&a<=10) print "obsolete"; else print "input error"}'
input error
input error
# echo "a b c\na b c"|awk -va=10 '{if (NF==3&&a>10) print NR,NF" fields, a>10"; else if (NF==2&&a<=10) print "obsolete"; else print "input error";exit}'
input error
# echo "a b c\na b c"|awk -va=11 '{if (NF==3&&a>10) print NR,NF" fields, a>10"; else if (NF==2&&a<=10) print "obsolete"; else print "input error";exit}'
1 3 fields, a>10
# echo "a b\na b"|awk -va=10 '{if (NF==3&&a>10) print NR,NF" fields, a>10"; else if (NF==2&&a<=10) print "obsolete"; else print "input error";exit}'
obsolete
# echo "a b c\na b c"|awk -va=11 '{if (NF==3&&a>10) print NR,NF" fields, a>10"; else if (NF==2&&a<=10) print {"obsolete";exit}; else {print "input error";exit}}'
 Syntax Error The source line is 1.
 The error context is
                {if (NF==3&&a>10) print NR,NF" fields, a>10"; else if (NF==2&&a<=10) print >>>  { <<<
 awk: 0602-502 The statement cannot be correctly parsed. The source line is 1.
 Syntax Error The source line is 1.
#

 

[PHV]

Replace this:
print {"obsolete";exit}
with this:
{print "obsolete";exit}

Hope This Helps, PH.
FAQ219-2884
FAQ181-2886

 

[yesornot]

thank you - also ; was causing error

print {"obsolete";exit};

replaced with
{print "obsolete";exit}

and it works now.