AWK fun with dates 1

[AnotherAlan]

Hi all,

I'm trying to come up with an awk statement that will give me the first Monday in the month.
I've got this so far, but it fails when the Monday is the 1st of the month. And it's not very elegant.
cal | awk 'NF >=6 {print $2}' | head -2 | tail -1

My AWK skills are very poor and I'm trying to learn, but what I guess I need is a way of finding the first non-blank field of $2 after $2=="M".

All help appreciated.
Alan

 

[AnotherAlan]

OK this is not quite correct;
"way of finding the first non-blank field of $2 after $2=="M"."

It's more an issue of how to deal with the Sunday being unpopulated and therefore Mondays date being $1 not $2.

This is Solaris btw, and 12 2008 is where it is failing.

Thanks

 

[PHV]

cal month year | nawk 'NF>=6 && NR>=3{print $(NF-5);exit}'

Hope This Helps, PH.
FAQ219-2884
FAQ181-2886

 

[AnotherAlan]

Many Thanks PH,

Best of all, I understand the logic.

Regards
Alan