awk - execution control??

[christiniaroelin]

Hi all,
i have two awk seperate statements in a script. But only the first one gets excuted and then exits. i replaced the second one with just a print statement as a test but i find the control not being passed after the excution od the first awk.. is this the normal behaviour of awk or is there a way around it that im missing.

Thank You
roelin

 

[vgersh99]

it would be helpful to see a sample code.

vlad
+----------------------------+
| #include<disclaimer.h> |
+----------------------------+

 

[christiniaroelin]

As an eample:

case ${channel} in
< case code here>
esac
exec awk -v stream=$channel '{ line[NR] = $0 } END {
i=NR
system( "banner -***********- >> /production/temp/outnlod"stream".dat")
system( "print VALIDATION PERFORMED ON- >> /production/sew/temp/outnlod"stream".dat")
system( "date >> /production/sew/temp/outnlod"stream".dat")
system( "print ------------------------------------- >> /production/temp/outnlod"stream".dat")
while( i > 0) {
system( "globber /production/data*/"stream"/*"line"nlod* >> /production/temp/outnlod"stream".dat" )
i=i-1 }
}' < dates.dat
exec awk '{ if ( ( $0 ~ / files found/) && ( $2 < 10) ) { print $2 " files found " } }' < outnlodl.dat

Thanks
roelin

 

[PHV]

In you shell man page pay attention to the exec builtin.

Hope This Helps, PH.
Want to get great answers to your Tek-Tips questions? Have a look at FAQ219-2884 or FAQ222-2244

 

[xmb]

are the double (( )) required by any (especially old) awks?
in

exec awk '{ if ( ( $0 ~ / files found/) && ( $2 < 10) ) { print $2 " files found " } }' < outnlodl.dat

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