awk and quotes 1

[tempest92]

hi,

can someone help please -

lsuser returns -

lsgroup -c -a id ALL
#name:id
system:0
#name:id
staff:1
#name:id
bin:2
#name:id
sys:3

i want the hostname:field1:field2 without the comments but my awk is not working !!

lsgroup -c -a id  ALL | awk -F: '$1 !~ /^#/ {print '`hostname`':$1:$2}'
 syntax error The source line is 1.
 The error context is
                $1 !~ /^#/ {print >>>  server1: <<<
 awk: The statement cannot be correctly parsed.
 The source line is 1.

thanks in advance !!

 

[feherke]

Hi

lsgroup -c -a id  ALL | awk -F: '$1 !~ /^#/ {print [red]"[/red]'`hostname`':[red]"[/red]$1[red]"[/red]:[red]"[/red]$2}'

Note that your code will run slowly because the [tt]hostname[/tt] executed for each line with match. Better execute it once and store its output in a variable.

lsgroup -c -a id  ALL | awk -vh="`hostname`" '!/^#/{print h":"$0}'

Feherke.

http://rootshell.be/~feherke/

 

[tempest92]

many thanks feherke. have a good day.