ARGV into a $var

[AcidHawk]

Hi

I'm trying to get the 3rd parameter to the last parameter put into a scalar variable.

I then want to split the scalar var(no problems here though..)

This is not working..

$var = @ARGV[2..$#ARGV];
print $var;

If i run this like so..

perl prog.pl useless useless var:i:want:up until this

$var prints out as only 'this'

I want $var to be 'var:i:want:up until this'

I don't know how many parameters are going to be sent to the command line.. I do want them all though, hence the need to use something like $#ARGV

is this possible..?
----
Of All the things I've lost in my life it's my mind I miss the most.

 

[toolkit]

Yes this can be done using the join command:

$var = join ":", @ARGV[ 2 .. $#ARGV ];

Cheers, Neil

 

[AcidHawk]

I just put " " around the ARGV stuff and it works..

$var = "@ARGV[2..$#ARGV]";
print $var;

Cheers
----
Of All the things I've lost in my life it's my mind I miss the most.