Any way to parse awk to just show me the host_name of a path?

[DeyfishinDemhills]

I'm a NetApp admin for a board design firm here in California. I'm trying to automate the host_name location of all Role Accounts that exist in our network.

I use ypcat on our proprietary auto.home file to locate the Role Account individually and awk to print just the second "chunk" of resulting information,

#ypcat -k auto.home | grep -w ireland5 | awk '{print $2}'

the result always spits out the entire path where this Role Account is homed,

TCP-hombre02:/vol/vol01/Roleaccounts/&

What I really want is a result with JUST THE HOST_NAME, "TCP-hombre02" and nothing else. The path is important but I'm really interested in just the host.


Is awk really only limited to displaying a specific "chunk" as defined by value of x, as in {print $x]? If so, then how can I meet my goal of discovering a Role Account's host w/o the appending path?

Ideally, if I can figure this out I can automate discovery of thousands of RAs in our system and print this information to other maintenance applications in the enterprise.

many thanks,
FF#24

 

[stanhubble]

you could just add -> cut -d":" -f1 to the end of your line

#ypcat -k auto.home | grep -w ireland5 | awk '{print $2}'| cut -d":" -f1

or you can get into substr and index within the awk statement

 

[Annihilannic]

If you change the field separators to be spaces and colons (add tabs too if necessary), you can do this:

#ypcat -k auto.home | awk -F'[ :]+' '/ireland5/{print $2}'

Also, as you can see, no need for grep when you're already running awk.

Annihilannic
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