Hello Hokis
You don't say if the graphic is stored in the table sourcing the form or another table.
I am presuming the picture is stored in another table which has a foriegn key to the primary key in the table sourcing your form
If that is the case a query containing both tables linked on the key will put the graphic into the forms data source - provided the query is the data source used.
Once it is in the data sourcing your form
put the picture field on to your form and name it
tnen
set the visible property to false
You can then on the on click property event of the check box
type something along the lines below
this should make it visible if hidden an invisible if shown
on clicking you check box
-picname being replaced with the name of the picture object name
Code:
if me.picname.visble = true
then
me.picname.visible = false
elseif me.picname.visble = false
then
me.picname.visible = true
end if
Hope this is what you are trying to do
regards
jo