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Access

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Swi

Programmer
Feb 4, 2002
1,966
US
Could you tell me why this expression works in Access 97 but not in Access 2003?

=IIf([Forms]![Job File]![JOB ITEMS Query].[Form].[RecordsetClone].[RecordCount]=0,0,[Forms]![Job File]![JOB ITEMS Query]![TxtExtended])

I know it has something to do with the [RecordsetClone].[RecordCount] property, but I tried everything and still it returns the #Name? value.

Thanks.

Swi
 



You might get better results in one of the many MS Access forums.

Skip,

[glasses]Just traded in my old subtlety...
for a NUANCE![tongue]
 
I'd try this:
=Nz([Forms]![Job File]![JOB ITEMS Query]![TxtExtended],0)

Hope This Helps, PH.
FAQ219-2884
FAQ181-2886
 
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