About dynamic memory allocation

[mrhegemon]

Are you not allowed to use the delete[] operator on an array that was dynamically allocated in a function with new?

e.g.,

void func1()
{
   ...

   double *a;

   func2(a);

   delete[] a;

   ...
}

void func2(double *a)
{
   ...

   a = new double[N];

   ...
}

I am confused about this. It seems to work in part of my code, but leads to segmentation faults in others.

 

[itsgsd]

Yes, you can use delete[] as you have, the problem is that you need to pass the address of your pointer a to func2 (pass by reference rather than by value):

void func1()
{
   ...

   double *a;

   func2(&a);

   delete[] a;

   ...
}

void func2(double **a)
{
   ...

   *a = new double[N];

   ...
}

 

[uolj]

itsgsd is right, but for the fun of it here's the same using a reference to a pointer instead of a double pointer. It makes it a little easier to call and use inside the funtion.

void func1()
{
   ...

   double *a;

   func2(a);

   delete[] a;

   ...
}

void func2(double *&a)
{
   ...

   a = new double[N];

   ...
}