4 log files are produced by 1 scrip

[maxcrook]

4 log files are produced by 1 script that runs on one of my aix boxes,the log files are numbered sequentially and start as follows.

1234.LOG
1235.LOG
1236.LOG
1237.LOG
I have a script that checks one log at a time.
However I want the user to type in the 1st log
ie. 1234.LOG and then check the remaining 3 logs without the user entering 4 separate log numbers.The result would then be output to the screen.

 

[alexhu]

Seems you like making work

Why not change the script so it only outputs one log ?

Alex

 

[KenCunningham]

Something like (quick and dirty)?:

pg $1.log #(where $1 is the user-supplied first number)
COUNT=1
NEXT=$1
while [ $COUNT -le 3 ]
do
NEXT=`expr $NEXT + 1`
pg $NEXT.log
COUNT=`expr $COUNT + 1`
done

Hope this helps.

 

[maxcrook]

The script is hard coded.Therefore im not able to change the output to 4 logs.

I have tried the script above and it does exactly what i want it to do.

Thanks

Max

 

[maxcrook]

Apologies - Have not looked at the output of this and it only searches the 1st LOG. Is there something missing ?

 

[KenCunningham]

Max, this is the first mention of 'searches' in this thread. Can you clarify exactly what you mean, please? Are you searching for a specific string, for example? Cheers.

 

[KenCunningham]

OK. If I'm reading this correctly now, you want the hard coded script to pick up the sequential numbers too?

If so, take out the pg $NEXT.log line and replace it with:

<name of your checking script> $NEXT.log

Note that this assumes that your hard coded script accepts the file name as it's parameter.

If this is an incorrect interpretation, let me know and we'll see what we can do. Cheers.