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- Users: pinkerton2002
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Newbie question: List from DB
Thank you, this helped me alot!! The connection was there, but I had forgotten to select the database..Thanx all.. That was really a nwbie-error!!- pinkerton2002
- Post #14
- Forum: PHP
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Newbie question: List from DB
Is there a way to be absolutely positive 100% sure that the connection to the db is working here as well?- pinkerton2002
- Post #12
- Forum: PHP
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Newbie question: List from DB
The names of the fields in the DB (gjest) is: id-integer autoincrement navn Varchar(35) hjemmeside Varchar(35) tid Varchar(35) melding (text) The connection works on another page, so it should be working here as well- pinkerton2002
- Post #11
- Forum: PHP
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Newbie question: List from DB
<?php include ("conn.php"); //this is the statement to get all the info $sql = mysql_query("SELECT * FROM gjest"); // go through each row in the result set and display data from the table while ($row = mysql_fetch_array($sql)) { // give a name to the fields i.e. $row['name of column in...- pinkerton2002
- Post #9
- Forum: PHP
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Newbie question: List from DB
<?php include ("conn.php"); //this is the statement to get all the info $sql = mysql_query("SELECT * FROM gjest"); // go through each row in the result set and display data from the table while ($row = mysql_fetch_array($sql)) { // give a name to the fields i.e. $row['name of column in...- pinkerton2002
- Post #8
- Forum: PHP
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Newbie question: List from DB
Thank you, but no, It doesent help me.. I still get the same error-message:[i] Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource [i] Now I've tried to echo them, but it still doesnt work...- pinkerton2002
- Post #7
- Forum: PHP
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Newbie question: List from DB
Thank you, but I still got the same error. And what is the difference between using ' ' and " "?- pinkerton2002
- Post #4
- Forum: PHP
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Newbie question: List from DB
This is my code: <?php $sql="SELECT * FROM gjest"; $query=mysql_query($sql); while($datas=mysql_fetch_array('$query')){ ?> Navn:<?php echo $datas["navn"]."<br>"; ?> Hjemmeside:<?php echo $datas["hjemmeside"]."<br>"; ?> Dato:<?php echo $datas["tid"]."<br>"; ?> Melding:<?php echo...- pinkerton2002
- Thread
- Replies: 14
- Forum: PHP
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Problems with inserting into database from form
YES!! Thank you very much Chacalink!!- pinkerton2002
- Post #5
- Forum: PHP
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Problems with inserting into database from form
Ok,thank you, I tried, still the same message. Her is the sql i get : INSERT INTO gjest(navn, hjemmeside, tid, melding) values(dsf, fdsf, Mon Jan 31, asf) This looks allright dont it? All the rights are set for the user who inserts into the DB- pinkerton2002
- Post #3
- Forum: PHP
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Problems with inserting into database from form
My code in the form is this: <form method= "post" action="process.php"> Navn : <input type= 'text' name= '$navn' > <br><br> Hjemmeside : <input type= 'text' name= '$hjemmeside' > <br><br> Comment : <input type= 'text' name= '$kommentar' > <br><br> <input type= 'submit' value= 'Skriv inn' >...- pinkerton2002
- Thread
- Replies: 4
- Forum: PHP
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Need help with this method
Thank you very much!! This helped me..- pinkerton2002
- Post #7
- Forum: Microsoft: ASP (Active Server Pages)
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Need help with this method
it is meant to count the numbers allowed in the databasefield. (lengde=length) Just to assure you, i have opened the database rs with this code: <% option explicit Dim rs, Conn, Kurskode, Kursnavn, Klassetrinn, Rom, Periode, Valgfag, sql, sql2, rs3 response.buffer = false Set Conn =...- pinkerton2002
- Post #3
- Forum: Microsoft: ASP (Active Server Pages)
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Need help with this method
<% If Request.QueryString ("knapp") = "ny" then 'administrator vil legge inn nytt kurs sql2="select * from Kurs" response.write sql2 rs3.open sql2, Conn, 3, 3 rs3.Addnew lengde= RS3("Kurskode").DefineSite verdi=request.queryString("Knr") if len (verdi)>lengde then RS3("Kurskode")=left...- pinkerton2002
- Thread
- Replies: 6
- Forum: Microsoft: ASP (Active Server Pages)
