Duh... figured it out...
First my reference at the top of my xsl was wrong...
Updating it to:
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
Meant that name() function of xpath was available. Then I simply used
<xsl:value-of select="name(*)"/>
Thanks!
I am using XSL to display one of many XML files to users... in Internet Explorer. Everything is identical in the structure of the each of the XML files except the first/root node. First example:
<?xml version="1.0"?>
<?xml:stylesheet type="text/xsl" href="test.xsl"?>
<Signature>
<item>...
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Do a search for the products you want to sell, on the left side, there's an option to search completed listings. Sort results by highest and lowest prices, see what the average price...
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I did find a way using the HTMLBody property ... thank you...
Here's my code in case someone comes across this post and has similar needs.
Dim olApp As Outlook.Application
Dim objMail As Object
Dim fs As Object
Dim f As Object
Dim ts As Object
Dim strHTMLBody As String...
I am trying to help a former collegue with a system that isn't quite working right for them right now.
They have an web page that is used only internally, that takes as input several xml files. These xml files indicate different options that the end user can select to pick pre-defined canned...
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