Search results for query: *

Can some one tell me what's wrong with the following mysql_query? mysql_query("select $move from moves where game_num = '$ID' && color = 'blue'", $db); The error returned by mysql_error() is You have an error in your SQL syntax. Check the manual that corresponds to your MySQL server version...

How would one get the first character of a string, regardless of what it is? I've looked through the PHP manual briefly and nothing looked obvious. ex. $string = "somestring"; $string = somefunction($string); // returns "s

I suppose I'll just have to update the row clearing all the entries (besides the keys). I'm designing an online game and I want to clear a move list after the script is done processing the data for that round.

Is there any quick way to clear a table row without deleting it?

nevermind again :). I was looking for help in the mysql forum and as I was explaining that all the variables were set I got to thinking...maybe they're not. Turns out I forgot to pass a session ID in the query string

the second code block produces an error.

assuming all variables are set and $db is a valid link resource and mysql_error() returns nothing and the table exists with the specified column names, what is wrong with the following statement? $piece_update = mysql_query("UPDATE `moves` SET `$move_from` = '$moves[$foo]', `$move_to` =...

I don't know why you need parenthesis there... that seems odd to me. oh well.

those functions should still be there. I'm writing code right now that's using those and it works fine (I have the same version of PHP). You might check your php.ini settings...

can someone look at this function and tell me what's wrong? I'm getting the following error: Parse error: parse error, unexpected T_VARIABLE in (file name) on line 13 function store_data($db, $ID, $color, $moves) { for($i = 1, $foo = 0; $i <= 12; $i++, $foo += 2) { $foo2 = $foo + 1...

I can't find a probem in the following mysql_query, though it is working fine. All the variables are set and contain correct data but the table is not being altered. mysql_query("UPDATE `moves` SET `$move_from` = '$moves[$foo]', `$move_to` = '$moves[$foo2]' WHERE `ID` = '$ID' && `color` =...

In case anyone wondered, there is a way around this with the chr function

what is a "character variable"?

that didn't work either... What is meant by "character variables"?

so, if I made it a string, could I get away with it? (example $var = "foo" $var-- would give me "fon")

It didn't. Output is at http://www.thespaz.net/games/board_display.php and source follows <? $var = "c"; $i = 3; print $var; print "<br>"; print $i; print "<br>"; $var--; $i--; print $var; print "<br>"; print $i; ?> If you need to see the php.ini file, it's at...

Ok, thanks, that documentation cleared it up. {}

I know that if you have a variable $var = "c", you can say $var++ and $var now equals d. Can you autodecrement $var? (I used $var-- and it didn't change the value).

and that is function field_or_forest($pos)

oops, sorry. Meant to include the worlds most massive if statement :) if ($pos == "a1" || $pos == "a2" || $pos == "a3" || $pos == "a4" || $pos == "b1" || $pos == "b2" || $pos == "b3" || $pos == "b4" || $pos == "b5" || $pos == "b7" || $pos == "b10" || $pos == "c1" || $pos == "c3" || $pos ==...