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I am working on a Linux server and need to ftp some files to it, but when I check the ifconfig, it comes up with MULTICAST BROADCAST. Does anyone know how I can determine what IP address I need to use to do the ftp? Any info would be great.

I am looking to take: INT32 num[45]; INT32 mod[3]; INT32 ans[4]; (the num and mod arrays get set to values here) I've tried: ans = num % mod; &ans[0] = (INT32*)(num & mod); ...but can't get it to work. Is it possible to do a mod calculation using arrays for all of the operands?

I thought that resolved my error, but it didn't. I'm still getting 'Illegal types for operands: 'unary *', and don't know why.

Yes! Thank you.

I get the following error: Illegal types for operands: 'unary *' From the following C code: unsigned int Add(unsigned int Aoperand, unsigned int Asize) { SET_PKA_PKCP_REG_A(Aoperand, Asize); //error points here } where: #define PKA_CONTROL_REG_ADDR 0x01006000 #define...

Using Visual C++. Don't have compiler on unclassified network, so I don't know what you'll be missing if you try to compile. Main.h code: extern UINT16 ARCFOUR_Sbox; typedef struct arcfour_state { UINT16 ij; UINT16 reserved; UINT16 salt[10]; Pointer32 part0; Pointer32...

Unfortunately, I am working on a classified system and cannot post the program. I had to slightly modify the code as it is.

I have the following: UINT16 ARCFOUR_Sbox[256]; VPTR ptr; ptr = &ARCFOUR_Sbox[64]; and I get the errors: C2109: subscript requires array or pointer type C2102: '&' requires l-value Does anyone know what is wrong with 'ptr = &ARCFOUR_Sbox[64];'?

I have a line of code as follows: S_ptr = (BYTE*)&ARCFOUR_Sbox[0]; ...where S_ptr is a Byte* and ARCFOUR_Sbox is a UINT16. I get the errors: C2109: subscript requires array or pointer type C2102: '&' requires l-value Can anyone tell me what's wrong with the line of code?

Has anyone ever seen a C struct like the following: typedef struct { UINT32 process_id; UINT32 sig_num; void(*callback)(int device_num); } UDM_NOTIFY; I don't understand that the 'void...' line is. Thanks for any help.