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The substitution is actually inside a for loop which searches through folders and returns the filename. I wanted to pass in the original(source) and new(dest) regular expressions as strings on the command line (using ARGV[1] etc). (the original filename 'format' isn't the same in each folder, so...

Unfortunately that doesn't work either. In the example shown, the output is data $1 The output should be data 35

I am doing a find-replace on filenames which are 2 numbers then description. I need to transform the filenames. I would like the 2 parts of the substitution as variables (so that I can pass in on the command line). I show a cutdown version here. This works: my $source = "(\\d\\d)(\.\*)" ; $_ =...

Thanks again for your quick reply. However, I have implemented an operator= function in BOTH the template AND the derived class (see below). Perhaps my question should then be, what is wrong with my declaration of operator= in the base template and derived class? In this case I do not actually...

Thanks. I am aware operator=, copy constructor etc are not inherited, hence in the derived class I am calling the base class' operator=. Even without doing that a default operator= should be called in the derived class which would do something, but I would not expect a compile error. I am...

I have a template class template<class T> class WavesetTemplate { public: ... WavesetTemplate<T>& operator=( const WavesetTemplate<T>& ); friend WavesetTemplate<T> operator*(const WavesetTemplate<T>& lhs, const WavesetTemplate<T>& rhs); protected: vector<vector<T> > m_TemplateData; ... }; and...

If you want to put the implementation in the .cpp file and you know what the template parameters will be, put the following at the top of your .cpp file: #pragma warning(disable: 4660) template class YourTemplate<double>; template class YourTemplate<complex<double> >; etc JonnoA