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hi all, how to write a connection statement in JSP for Microsoft SQL Server 2000? is a driver file needed? if so where to get them? thanks

how to exit microsoft access totally aft clickin a button? thanks..

i tink i explain from the start... the main form is to display a person information which includes his car number,then the subform is to display the number of traffic offences he has commits.. some of them has more than 1 offences.now i wan to open a form that is link with the record i...

wat i mean is it cant find that field...not cant find fldName2..i hav alreadi change it to the field i wan to find..the field is in the subform

i use ur codes but it say i cant find fldName2..

i tried that but cant get it to work...i explain again,the subform is showing a list of records,now i wan to add details to a specific record in the subform,i wan to open the form with the criteria of the choosen record...can it be done?

i wan to open a form using selected id in a subform as criteria....how can i do it?...thanks

it juz say unable to create thats all...i tried to compile n there is no error still it is unable to create MDE file..

when i try to convert my file to mde..it tell me that the database could not be converted to MDE...wat could be the prob?

any question bout the codes..pls feel free to ask..i will reply asap.. *********************************************************** Option Compare Database Private m_objWord As Word.Application Private m_objDoc As Word.Document Public Sub CreateWord() Dim m_strDIR As String m_strDIR =...

"class does not support automation or does not support expected interface"...what is tis error?... tis is my code Public Sub sentMail() Dim objOutlook As New Outlook.Application Dim objMessage As MailItem Set objOutlook = CreateObject("Outlook.Application") Set objMessage =...

i found the solution in a book thanks anyway..

Public Function CreateWord(strDocuPath As String) 'function returns nothing, but I created this as a 'function so all those macro users out there could 'use it also. :P 'if no path is passed to function, exit - no further 'need to do anything If IsNull(strDocuPath) Or...

thanks eupher..i recreat the form n the form works fine...

i wan to open a report from my form...when i click the button to open the report...it gave me a error "Data type mismatch in criteria expression"...whats wrong?...can someone help?... my code Private Sub Command12_Click() On Error GoTo Err_Command12_Click DoCmd.OpenReport...

the value is created in a subform countin the number of records..then show in main form...at the subform footer i put a textfield which count the records wif count(*)..then i show it in the textfield in main form...how can i do it...i try to count it in the subform but its still the same n it...

i got a problem onli when the value is equal to 3 then the msgbox will appear,value greater than 3 does not make the msgbox appear...wat is wrong wif my code?... If Me![Text21] >= 3 Then MsgBox "xxx" End If

can anione help???

hi Bob the value in the textbox is auto calulated thru number of records in the subform.. i tried after update and on dirty but could not work.. actually wat i wan is..if textbox value is equal or greater than 3 then i wan to popup a reminder..is there a better way to do it?.. Jo

when a textbox value is equal or greater than 3 i wan to open a form...how can i do it?thanks...