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Help on "ls -l $* ¦ awk '{ print $9}'+ grep $9 pattern>> result"
You can use AWK to do the regular expression match without needing to subsequently grep - e.g. ... ls -l * | awk '/regexp/ print $9' or grepping a specific field .. ls -l * | awk '$n =~ /regexp/ print $9' sorry it's been a while but I think syntax is correct
