I have input string
Input val=195.4,280.0,,,301.3,,,441.9,
In that i need to elemnate the empty"" values...
Expected output is:195.4,280.0,301.3,441.9,
Sot
Dear George,
Inputs:
dx1=195.4,195.4,195.4,441.9,569.5,301.3
dx2=301.3,280.0,280.0,842.13,980.9
on error resume next
Dim sol,val
set sol=CreateObject("Scripting.Dictionary")
for i=1 to 6
'sol.Add a(i),1
sol.Add dx1(i),1
sol.Add dx2(i),1
'sol.Add c(i),1...
George,
I tried ur example....
I am getting the following error
Error Type:
Microsoft VBScript runtime (0x800A01C9)
This key is already associated with an element of this collection
Ragards,
Sot
I have 4 diffrent array a(6),B(6),C(6) and d(6)
a(6) contains 120,120,145,326,145,120
b(6) contains 333,120,145,336,145,120
c(6) contains 120,444,145,326,145,444
d(6) contains 333,120,145,326,145,120
I want to eleminate the duplicate value each array and append in an single new array..
Note...
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I am using crystal reports 8.5 and ASP
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Ravi
I am using crystal 8.5/Sqlserver 2000
In my crystal reports..I am trying to use view(visit_accledger_rpt_vw
AS) and stored procedure(sp_GetFinancial)...
i am trying to get a value(@get_max_detailno_withinIns) from view and pass the value to stored procedure as a parameter(@transno)
and try to...
Happy new year...
I am using crystal 8.5/Sqlserver 2000
In my crystal reports..I am trying to use view(visit_accledger_rpt_vw
AS) and stored procedure(sp_GetFinancial)...
i am trying to get a value(@get_max_detailno_withinIns) from view and pass the value to stored procedure as a...
In first row i am trying to display paid_id(thru @Financial)--- which is fine
In second row i am trying to display paid_amt(thru @Financial)--which is fine
In third row i am trying to display paid_id(thru @Balance)
this line is confusing me it gives always 0.00
am using 2 formulas(@Finacial,@Balance)in my report.
In both formula I have inserted same database table field({Visit.pay_id}).
If run the report, i am not getting the database value
where i have insert the second formula(@Balance). only 0 i am getting.
But in the first formula(@Finacial) i am...
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