if subnet mask is 255.255.255.248 then
Subnet ID is 62.232.142.216
Subnet Broadcast is 62.232.142.223
so available IP should be
62.232.142.217 ~ 62.232.142.222
since router internal IP use 217
PIX outside IP use 219
NAT should be 220 ~ 222, only three
PAT can use 218
Am I right?
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