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Thank you, Cakiwi ! Gilles

Alleluia !! ;)

sed 's/://g' means that you will substitue ("s") each ":" with ...nothing (/://)in each line (g). Gilles

A possible solution : find your_search_path -mtime -1 -type f -ls | sed 's/://g' | awk '$10 < your-hour_without_: {print $11}' | xargs rm It workes but,surely, there's abetter way to do it. Bye, Gilles

Hi, $11 means the field #11 of output for &quot;ls -al&quot; (the name of the file). To complete the Mrjazz solution's, i think you can try : find your_search_path -mtime -1 -type f -ls | grep 08:30 | awk ´{print $11 }´ | xargs rm Regards, Gilles

Try sed 's/&quot;\[]//g' filename. :)

oups ! didn't see there's so many people ! (sorry,i use logfailed.sql for infile) Bye, ;-)

Why don't you use a curde method with head and tail ? For example : #!/bin/ksh i=1 cat logfailed.sql | while read line do case $i in 12) head -26 infile | tail -1 >> outfile i=`expr $i + 1` ;; 13) head -14 infile | tail -1 >> outfile...

I believe that for several OS, you have a command to display the activity for a process. On Sun, it's truss, on SGI, it's par and for the other i don't remember ... You may see if there's no Read/write activity. Good Luck, Gilles

GREAT ! It workes, thank you very much !

Hi, my problem is that i can't have &quot;'&quot; in my output, for example : awk '{printf &quot;'%s'\n&quot;,$1}' file to have something like : 'Field#1' \',&quot;'&quot;,&quot;''&quot;... doesn't work (even with command print). Thanks a lot !