Tek-Tips is the largest IT community on the Internet today!
Members share and learn making Tek-Tips Forums the best source of peer-reviewed technical information on the Internet!
-
Congratulations IamaSherpa on being selected by the Tek-Tips community for having the most helpful posts in the forums last week. Way to Go!
Search results for query: *
- Users: Inexperience
- Order by date
-
Simpson 1/3 Program Errors
Yes I did I corrected the declaration portion. Then made sure the variables matched from the main program to the function and it now puts out a value. It is not correct so it is a math issue which I will hunt down. Thank you for the help it is greatly appreciated!!- Inexperience
- Post #8
- Forum: Fortran
-
Simpson 1/3 Program Errors
This second post was an accident please ignore it. Thank you- Inexperience
- Post #6
- Forum: Fortran
-
Simpson 1/3 Program Errors
So I declared n as an integer in the function and declared the h division to produce an actual value but it is still producing a 0 value. Anymore advice? This is what I have now... Program test IMPLICIT NONE REAL :: Simpson13 INTEGER, DIMENSION(7) :: V INTEGER :: h,n,simp13 V =...- Inexperience
- Post #5
- Forum: Fortran
-
Simpson 1/3 Program Errors
So I made the changes but I am still having outputs of zero. Anymore help? This is what I have now... Program test IMPLICIT NONE REAL :: Simpson13 INTEGER, DIMENSION(7) :: V INTEGER :: h,n,simp13 V = (/1.000,1.167,1.333,1.500,1.667,1.833,2.000/) h = 0.1667 n = 6.0 Simp13=Simpson13(V,h,n)...- Inexperience
- Post #3
- Forum: Fortran
-
Simpson 1/3 Program Errors
I am very new to fortran and I have been assigned to write a Simpsons 1/3 function. Below is what I have come up with but it is outputting the area as 0. All help is greatly appreciated. Program test IMPLICIT NONE REAL :: n, simp13, Simpson13 INTEGER, DIMENSION(10) :: V INTEGER :: h V =...- Inexperience
- Thread
- Replies: 7
- Forum: Fortran
