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mikrom, Thanks for the response. To me, "external" contains no information of the subroutine. My understanding is: "external" can be anything and the language leave this room for the linker. I don't know for sure why there is a seg fault. But I'd expect this is due to the FORTRAN standard...

Sorry, I made some grammar mistakes in the code, I have no idea how to edit the reply.

mikrom, Yes, I agree. But it doesn't compile if I make interface generic. For example subroutine poly(another_subroutine, A) class(*), intent(inout) :: A interface another_subroutine subroutine another_subroutine(AA) class(*), intent(inout) ::AA endsubroutine subroutine another_subroutine(AA)...

Thanks for your time and response mikrom. But I think there is some misunderstand here. In your example code, you shown that "a subroutine can take unlimited polymorphic types as imput parameters". My question is "Is it possible to make subroutine take unlimited polymorphic subroutines as well...

I am programming with FORTRAN oop features. Now I have a subroutine which takes another subroutine as its argument. But I want the subroutine takes unlimited polymorphic subroutine as the argument as well as normal subroutine. For example I have: subroutine PassFunc(MyFunc, MyInput)...