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passing address to sprintf()
That was my impression (that it was valid). Problem is that it accesses the data rather than the address of the data. &buff2[2] and buff[2] are equivalent... and I did not think they should be... I very much did not think they should be... bug in the compiler? Thanks for the post.- randomprocess
- Post #3
- Forum: C
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passing address to sprintf()
How do I do this guys.... char *buff2 = " "; // is malloc'd in real code. sprintf(&buff2[2],"xx"); // is sprintf(&buff2[2],"%02X",*ptr) in real code. printf("%s\n"); obviously trying to write "xx" to &buff2+2 and &buff2+3.- randomprocess
- Thread
- Replies: 3
- Forum: C
