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  1. kapahianil

    Fortran Gurus, Please comment!!

    Hi, I am still confused now I have added u to cell type. And when I allocate memory for that I get error that forrtl: severe (174): SIGSEGV, segmentation fault occurred. But If I do Allocate(basecell(0:1000)%cptr), there is no error and things work fine. Thanks Anil Program TEST IMPLICIT...
  2. kapahianil

    Fortran Gurus, Please comment!!

    Hi xwb!! I understand that I need it for anything that accesses %cptr%. But Then how come this thing still prints PRINT*,"basecell(0)%cptr%nbrcell(iside)%cptr%index(1),"iside=",iside even if I don't allocate "ALLOCATE(basecell(i)%cptr)". Thanks Anil
  3. kapahianil

    Fortran Gurus, Please comment!!

    Please have a look at piece of code below and try to answer the questions given in comments. Thanks. Anil Program TEST IMPLICIT NONE INTEGER :: nch, iside, i ! cell pointer type TYPE...

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