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void main () { int i = 0; char a[50], b[25]; printf ("Enter first string>"); while ((a[i++] = getchar() )!= '\n'); printf ("Enter first string>"); gets(b); for (int j = 0; b[j] != '\0'; j++, a[i+j] = b[j]); a[i + j] = '\0'; printf ("a + b =...

hi, I think this should work find; void main () { int arr[4][5], row = 4, col = 5; .... print_array (arr, row, col); } void print_array(int arr[][5], int row, int col) { for (int x = 0; x < row; x++){ for (int y = 0; y < col; y++) printf (&quot;%d &quot;, arr[x][y])...

The last line should be: printf(&quot;The filename is: %s\n&quot;, zipFileNames[userPrintAnswer]); Andrew Lim Trying and exploring is adventuring

you may use char * as the data type for passing in returning a string, example: char* func (char * a) { char b[5] = &quot;halo&quot;; //codes are here return b; } Andrew Lim Trying and exploring is adventuring

/*Duplicate the new string*/ char* duplicate(char text[]) { char text2[50]; strcpy (text2, text); return strcat(text2,text); } char text2[100]; strcpy (text2, duplicate(text)); printf(&quot;\tThe duplicated string is: %s.\n&quot;, text2); x-)I don't really get what you mean...

It's somehow like printf (&quot;%d&quot;, temp = a + b); and printf (&quot;%d&quot;, a + b);